Problem Find the Cartesian equation of the curve represented by $x = 4t + 3$ and $y = 16t^2 - 9$, -∞ < t < +∞.

Answer Key

Solution

$t = \dfrac{x - 3}{4}$

$y = 16t^2 - 9$

$y = 16\left( \dfrac{x - 3}{4} \right)^2 - 9$

$y = x^2 - 6x$ ← answer

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